Segitenétek megoldani az alábbi matematika műveleteket?

1.
b) `(-5/17)*1 1/16 = -5/cancel 17*cancel 17/16 = -5/16`

c) `1 1/3*(-4 4/5) = 4/cancel 3*(-cancel 24_8/5) = -(4*8)/5 = -32/5`

d) `38/63:19/18 = cancel 38_2/cancel 63_7*cancel 18_2/cancel 19 = (2*2)/7 = 4/7`

e) `(-1 21/30)*(-20/21)*(-45/68) = (-cancel 51_17/cancel 30_3)*(-cancel 20_2/cancel 21_7)*(-45/68) = cancel(17*2)/(cancel 3*7)*(-cancel 45_15/cancel 68_2) = -15/14`

f) `(+33/35):(-15/42) = cancel 33_11/cancel 35_5*(-cancel 42_6/cancel 15_5) = -(11*6)/(5*5) = -66/25`

g) `(-14/25):28/45:(-3) = -cancel 14/cancel 25_5*cancel 45_9/cancel 28_2*(-1/3) = -cancel 9_3/10*(-1/cancel 3) = 3/10`

h) `(+12):(-8/27):2 1/4 = cancel 12_3*(-27/cancel 8_2):9/4 = -(3*cancel 27_3)/cancel 2*cancel 4_2/cancel 9 = -3*3*2 = -18`

2.
a) `cancel 2/cancel 3*cancel 3/cancel 4_2-("0,25") = 1/2-cancel 25/cancel 100_4 = 1/2-1/4 = 2/4-1/4 = 1/4`

b) `2/5*"0,01"+1/10*"0,6" = cancel 2/5*1/cancel 100_50+1/10*cancel 6_3/cancel 10_5 = 1/(5*50)+3/(10*5) = 1/250+3/50 = 1/250+15/250 = 16/250 = 8/125`

c) `(-"8,7"):(5/7-"0,3") = (-87/10):(5/7-3/10) ``=`` (-87/10):(50/70-21/70) ``=`` (-87/10):29/70 =`
`= (-cancel 87_3/cancel 10)*cancel 70_7/cancel 29 = (-3)*7 = -21`

d) `5/2:3/4+1/3:1/7 = 5/cancel 2*cancel 4_2/3+1/3*7 = 10/3+7/3 = 17/3`

e) `(3/cancel 8*cancel 24_3+(-9))*"32,25" = (3*3-9)*"32,25" = 0*"32,25" = 0`

f) `(-9+3/10):(5/7-"0,3") = (-90/10+3/10):(5/7-3/10) = -87/10:(50/70-21/70) ->` ugyanaz, mint a c)