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8,
a,
`1/2-(5/6-6/7):4/21` = `1/2-((5*7-6*6)/42)*(21/4)` = `1/2-(-1/2*1/4)` = `1/2+1/8` = `5/8`
b,
`(1/2-5/6-6/7):4/21` = `((21-35-36)/42)*21/4` = `-50/2*1/4` = `-50/8` = `-25/4`
9,
a, igaz, pl `root()(2)*root()(8)` = `root()(16)` = 4
b, igaz
c, hamis, pl. `root()(4)` = 2
10,
A = `2.56*10^(11)`
B = `-4.5*10^(11)`
C = `1.6*10^(-11)`
D = `-9*10^(-12)`
11,
`2.56*10^(11)*1.6*10^(-11)` = `2.56*1.6*10^(11)*10^(-11)` = `4,096*10^0` = 4,096
`-4.5*10^(11)*(-9*10^(-12))` = `4.5*9*10^(11)*10^(-12)` = `40.5*10^(-1)` = 4,05
Az első szorzat a nagyobb.
12,
`(2.56*10^(11))/(1.6*10^(-11))` = `2.56/1.6*10^(11-(-11))` = `1.6*10^(22)`
`(4.5*10^(11))/(9*10^(-12))` = `0.5*10^(11-(-12))` = `5*10^(22)`
A második hányados a nagyobb.
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