AG495
válasza
1 hete
3. első oszlop:
2x =16=24
Ha az alap egyenlő, akkor a kitevő is, eszerint: x=4
2x =8=23
x=3
23x =8=23
3x=3
x=1
25x-3 =16=24
5x-3=4
5x=7
x=7/5=1,4
24x-5 =64=26
4x-5=6
4x=11
x=11/4=2,75
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AG495
válasza
1 hete
32x =81=34
2x=4
x=2
3x =27=33
x=3
33x =27=33
3x=3
x=1
35x-3 =81=34
5x-3=4
5x=7
x=7/5=1,4
34x-5 =729=36
4x-5=6
4x=11
x=11/4=2,75
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AG495
válasza
1 hete
4x =64=43
x=3
5x =1=50
x=0
2x+4 =64=26
x+4=6
x=2
64x+3 =36=62
4x+3=2
4x=-1
x=-1/4=-0,25
53x-1 =125=53
3x-1=3
3x=4
x=4/3
(2/3)x =1=(2/3)0
x=0
7x =0
Ennek nincs megoldása
36x =-6=361/2
x=1/2=0,5
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AG495
válasza
1 hete
a)
2x =1/16=1/24 =2-4
x=-4
b)
2x =1/4=1/22 =2-2
x=-2
c)
2x =1/8=1/23 =2-3
x=-3
d)
2x =0
Ennek nincs meoldása
e)
2x =1/2=2-1
x=-1
f)
2x =1/32=1/25 =2-5
x=-5
g)
3x =1/3=3-1
x=-1
h)
3x =1/9=1/32 =3-2
x=-2
i)
3x =1/81=1/34 =3-4
x=-4
j)
3x =1=30
x=0
k)
3x =-1
Ennek nincs megoldása
l)
3x =1/27=33
x=3
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AG495
válasza
1 hete
9x =1/729=1/93 =9-3
x=-3
4x =1/4=4-1
x=-1
2-3x =1/4=1/22 =2-2
-3x=-2
x=2/3
10x =0,0001=10-4
x=-4
10x =0,01=10-2
x=-2
3x =1/9=1/32 =3-2
x=-2
5x 1/625=1/5
5-x =1/25=1/52 =5-2
0,5x =32=25 =1/2-5 =0,5-5
x=-5
2-4x =1/4=1/22 =2-2
-4x=-2
x=1/2=0,5
3x+1 =1/81=1/34 =3-4
x+1=-4
x=-5
2x+1 =1/64=1/26 =2-6
x+1=-6
x=-7
42x =1/8=1/23 =2-3
2x=-3
x=-3/2=-1,5
42x =1/8
(22 )2x =1/23
24x =2-3
4x=-3
x=-3/4=-0,75
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AG495
válasza
1 hete
343x =1/7
(73 )x =7-1
73x =7-1
3x=-1
x=-1/3
4x =32
(22 )x =25
22x =25
2x=5
x=5/2=2,5
3-x =243=35
-x=5
x=-5
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AG495
válasza
1 hete
4x =82x-1
(22 )x =(23 )2x-1
22x =26x-3
2x=6x-3
3=4x
x=3/4=0,75
495x-3 =7
(72 )5x-3 =7
710x-6 =71
10x-6=1
10x=7
x=11/10=7/10=0,7
32x-3 =814x+1
32x-3 =(34 )4x+1
32x-3 =316x+4
2x-3=16x+4
-7=14x
x=-7/14=-0,5
42x-1 =1/8=1/23
(22 )2x-1 =2-3
24x-2 =2-3
4x-2=-3
4x=-1
x=-1/4=-0,25
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AG495
válasza
1 hete
(1/3)3x-2 =81
(1/3)3x-2 =34
(1/3)3x-2 =(1/3)-4
3x-2=-4
3x=-2
x=-2/3
(1/5)2x+5 =125
(1/5)2x+5 =53
(1/5)2x+5 =(1/5)-3
2x+5=-3
2x=-8
x=-4
(1/9)4+2(x-3) =81
(1/9)4+2x-6 =92
(1/9)2x-2 =(1/9)-2
2x-2=-2
2x=0
x=0
(1/4)3-x =64x-3
(1/4)3-x =(43 )x-3
(1/4)3-x =43x-9
(1/4)3-x =(1/4)-3x+9
3-x=-3x+9
2x=6
x=3
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AG495
válasza
1 hete
3IxI =27=33
IxI=3
x1=-3
x2=3
3I3x-4I =92x-2
3I3x-4I =(32 )2x-2
3I3x-4I =34x-4
I3x-4I=4x-4
3x-4=4x-4
0=x
x1=0, de ez az eredeti egyenletnek nem megoldása
-3x+4=4x-4
7x=8
x2=8/7
9IxI-3 =3
(32 )IxI-3 =31
32IxI-6 =31
2IxI-6=1
2IxI=7
IxI=7/2=3,5
x1=-3,5
x2=3,5
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